Getting time to variable from time Input
Quote from asmat on May 26, 2024, 12:14 amHi everyone,
I'm working on a project and need to capture the time from a Time Input element into a JavaScript variable in the format HH:MM
AM/PM. Can anyone advise on how to achieve this?Thanks!
Hi everyone,
I'm working on a project and need to capture the time from a Time Input element into a JavaScript variable in the format HH:MM
AM/PM. Can anyone advise on how to achieve this?
Thanks!
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Quote from Gaev on May 26, 2024, 3:43 am@asmat
1) for the variable property of TimeInput1, change x to [x]
2) Now, when I select 1:07 AM, [x] is displayed as "1970-01-01T06:07:00.000Z" ... the date and time are separated by T
a) replace Z with nothing
b) replace double quotes with nothing
c)) parse the remaing text into an array using T as the separator ... the second array variable now contains 06:07:00.000
d) parse this into array using : as the separator ... the first two array variables are 06 and 07 ... let us call them [myHH] and [myMM] ... [myHH] is 5 more than i input because my local time (Toronto) is 5 hours behind UTC/GMT ... so add/subtract this amount to obtain the [myHH] in your locale.
e) if resulting [myHH] is greater than 12, subtract 12 from [myHH] and set [ampm] to "PM" ... else leave [myHH] as is and set [ampm] to "AM"
Your answer is [myHH]:[myMM] [ampm]
If I select 06:10 PM, applying logic 2 (a) to (e) above, [x] (displayed as "1970-01-01T23:10:00.000Z") will return 06:10 PM
Let me know if something is unclear or does not work.
1) for the variable property of TimeInput1, change x to [x]
2) Now, when I select 1:07 AM, [x] is displayed as "1970-01-01T06:07:00.000Z" ... the date and time are separated by T
a) replace Z with nothing
b) replace double quotes with nothing
c)) parse the remaing text into an array using T as the separator ... the second array variable now contains 06:07:00.000
d) parse this into array using : as the separator ... the first two array variables are 06 and 07 ... let us call them [myHH] and [myMM] ... [myHH] is 5 more than i input because my local time (Toronto) is 5 hours behind UTC/GMT ... so add/subtract this amount to obtain the [myHH] in your locale.
e) if resulting [myHH] is greater than 12, subtract 12 from [myHH] and set [ampm] to "PM" ... else leave [myHH] as is and set [ampm] to "AM"
Your answer is [myHH]:[myMM] [ampm]
If I select 06:10 PM, applying logic 2 (a) to (e) above, [x] (displayed as "1970-01-01T23:10:00.000Z") will return 06:10 PM
Let me know if something is unclear or does not work.
Quote from roccocogliano on May 26, 2024, 11:19 amHi @asmat, take a look at the attached example. where there is the following code in the change event of the time input. If I understand the problem, I think this is enough.TimeInputGetHour "[ora_input]" [h] TimeInputGetMinute "[ora_input]" [m] setvar [ampm] "AM" Ifex ([h] == 12) Setvar [ampm] "PM" Endif ifex ([h] > 12) math "[h]-12" 0 [h] setvar [ampm] "PM" endif setvar [h] "0[h]" StrCopy "[h]" -2 2 [h] setvar [m] "0[m]" StrCopy "[m]" -2 2 [m] setvar [ora] "[h]:[m] [ampm]"
Greetings Rocco
Hi @asmat,
take a look at the attached example.
where there is the following code in the change event of the time input.
If I understand the problem, I think this is enough.
TimeInputGetHour "[ora_input]" [h] TimeInputGetMinute "[ora_input]" [m] setvar [ampm] "AM" Ifex ([h] == 12) Setvar [ampm] "PM" Endif ifex ([h] > 12) math "[h]-12" 0 [h] setvar [ampm] "PM" endif setvar [h] "0[h]" StrCopy "[h]" -2 2 [h] setvar [m] "0[m]" StrCopy "[m]" -2 2 [m] setvar [ora] "[h]:[m] [ampm]"
Greetings Rocco
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Quote from roccocogliano on May 26, 2024, 1:18 pmThere is a small error in the app attached above, sorry. the code in the post is right
There is a small error in the app attached above, sorry. the code in the post is right