Assuming you mean an image stored in a field defined as a Picture Field, you will need to create a picture object for each picture field in the record. In the picture object properties type in the field variable (i.e. [db.table.picture]) where it asks for the file. The image in the picture object will change according to the record you select. Barring some really creative coding, I think you'll need a picture object for every picture field in your record.
Assuming you mean an image stored in a field defined as a Picture Field, you will need to create a picture object for each picture field in the record. In the picture object properties type in the field variable (i.e. [db.table.picture]) where it asks for the file. The image in the picture object will change according to the record you select. Barring some really creative coding, I think you'll need a picture object for every picture field in your record.
